View of On the rational difference equation \(x_{n+1}=\frac{x_n\cdot (\overline{a}x_{n-k}+ax_{n-k+1})}{bx_{n-k+1}+cx

x_{n + 1} = \frac{x_{n} \cdot (\bar{a} x_{n - k} + a x_{n - k + 1})}{b x_{n - k + 1} + c x_{n - k}}

$x_{n+1}=\frac{x_n\cdot (\overline{a}x_{n-k}+ax_{n-k+1})}{bx_{n-k+1}+cx_{n-k}}$ Download Download PDF